What are the solutions to the equation 4x^3-32x=0 ?

The solutions to the equation 4x^3-32x=0 are x=0,x=-2sqrt(2),x=2sqrt(2)

Find the zeros of 4x^3-32x=0

The zeros of 4x^3-32x=0 are x=0,x=-2sqrt(2),x=2sqrt(2)

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4 x^{3} - 32 x = 0

x = 0, x = - 22, x = 22

Decimal Notation

x = 0, x = - 2.82842 \dots, x = 2.82842 \dots

Solution steps

4 x^{3} - 32 x = 0

Factor

4 x^{3} - 32 x : 4 x (x + 22) (x - 22)

4 x (x + 22) (x - 22) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 22 = 0 or x - 22 = 0

Solve

x + 22 = 0 : x = - 22

Solve

x - 22 = 0 : x = 22

The solutions are

x = 0, x = - 22, x = 22

4 x^{4} + 9 = 37 x^{2}

x^{7} - 3 x^{5} + x^{2} - 2 x + 13

z^{4} + 6 (1 + i) z^{2} + 5 + 6 i = 0

x^{3} - 4 x^{2} + 25 x - 100 = 0

(x + 1)^{2} (x - 5) = 0

What are the solutions to the equation 4x^3-32x=0 ?
The solutions to the equation 4x^3-32x=0 are x=0,x=-2sqrt(2),x=2sqrt(2)
Find the zeros of 4x^3-32x=0
The zeros of 4x^3-32x=0 are x=0,x=-2sqrt(2),x=2sqrt(2)