What are the solutions to the equation (x+1)^2(x-5)=0 ?

The solutions to the equation (x+1)^2(x-5)=0 are x=-1,x=5

Find the zeros of (x+1)^2(x-5)=0

The zeros of (x+1)^2(x-5)=0 are x=-1,x=5

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(x + 1)^{2} (x - 5) = 0

x = - 1, x = 5

Solution steps

(x + 1)^{2} (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 5 = 0 : x = 5

The solutions are

x = - 1, x = 5

- 4 x^{3} = 32

r^{5} - r^{4} - 4 r^{3} - 4 r^{2} - 5 r - 3 = 0

x^{4} - 12 x^{3} - 14 x^{2} + 292 x + 577 = 0

2 x^{4} + 3 = 0

x^{3} - x^{2} + 6 x - 6 = 0

What are the solutions to the equation (x+1)^2(x-5)=0 ?
The solutions to the equation (x+1)^2(x-5)=0 are x=-1,x=5
Find the zeros of (x+1)^2(x-5)=0
The zeros of (x+1)^2(x-5)=0 are x=-1,x=5