What are the solutions to the equation -x^4+1=0 ?

The solutions to the equation -x^4+1=0 are x=1,x=-1,x=i,x=-i

Find the zeros of -x^4+1=0

The zeros of -x^4+1=0 are x=1,x=-1,x=i,x=-i

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- x^{4} + 1 = 0

x = 1, x = - 1, x = i, x = - i

Solution steps

- x^{4} + 1 = 0

Move

1

to the right side

- x^{4} = - 1

Divide both sides by

- 1

x^{4} = 1

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} = 1

Solve

u^{2} = 1 : u = 1, u = - 1

u = 1, u = - 1

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 1 : x = 1, x = - 1

Solve

x^{2} = - 1 : x = i, x = - i

The solutions are

x = 1, x = - 1, x = i, x = - i

x^{4} + 2 x^{3} + 22 x^{2} + 50 x - 75 = 0

r^{4} + 14 r^{2} - 14 = 0

x^{3} - 3 x^{2} - 25 x + 75

x^{3} - 8 x + 5 = 0

n^{3} - n = 9 n^{2} - 9

What are the solutions to the equation -x^4+1=0 ?
The solutions to the equation -x^4+1=0 are x=1,x=-1,x=i,x=-i
Find the zeros of -x^4+1=0
The zeros of -x^4+1=0 are x=1,x=-1,x=i,x=-i