What are the solutions to the equation 6x^4+2x^2-8=0 ?

The solutions to the equation 6x^4+2x^2-8=0 are x=1,x=-1,x= 2/(sqrt(3))i,x=-2/(sqrt(3))i

Find the zeros of 6x^4+2x^2-8=0

The zeros of 6x^4+2x^2-8=0 are x=1,x=-1,x= 2/(sqrt(3))i,x=-2/(sqrt(3))i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{4} + 2 x^{2} - 8 = 0

x = 1, x = - 1, x = \frac{2}{3} i, x = - \frac{2}{3} i

Solution steps

6 x^{4} + 2 x^{2} - 8 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

6 u^{2} + 2 u - 8 = 0

Solve

6 u^{2} + 2 u - 8 = 0 : u = 1, u = - \frac{4}{3}

u = 1, u = - \frac{4}{3}

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 1 : x = 1, x = - 1

Solve

x^{2} = - \frac{4}{3} : x = \frac{2}{3} i, x = - \frac{2}{3} i

The solutions are

x = 1, x = - 1, x = \frac{2}{3} i, x = - \frac{2}{3} i

r^{3} + r = 0

2 x^{4} - 19 x^{2} + 9 = 0

x^{3} - x^{2} + 3 x + 1 = 0

26.28 = 0.15 x^{3} + 0.3 x^{2}

x^{3} + 4 x^{2} + x + 4

What are the solutions to the equation 6x^4+2x^2-8=0 ?
The solutions to the equation 6x^4+2x^2-8=0 are x=1,x=-1,x= 2/(sqrt(3))i,x=-2/(sqrt(3))i
Find the zeros of 6x^4+2x^2-8=0
The zeros of 6x^4+2x^2-8=0 are x=1,x=-1,x= 2/(sqrt(3))i,x=-2/(sqrt(3))i