What are the solutions to the equation x^4-x^3-2x-4=0 ?

The solutions to the equation x^4-x^3-2x-4=0 are x=-1,x=2,x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of x^4-x^3-2x-4=0

The zeros of x^4-x^3-2x-4=0 are x=-1,x=2,x=sqrt(2)i,x=-sqrt(2)i

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x^{4} - x^{3} - 2 x - 4 = 0

x = - 1, x = 2, x = 2 i, x = - 2 i

Solution steps

x^{4} - x^{3} - 2 x - 4 = 0

Factor

x^{4} - x^{3} - 2 x - 4 : (x + 1) (x - 2) (x^{2} + 2)

(x + 1) (x - 2) (x^{2} + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 2 = 0 or x^{2} + 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 2 = 0 : x = 2 i, x = - 2 i

The solutions are

x = - 1, x = 2, x = 2 i, x = - 2 i

x^{3} + 4 x + 4 = 0

x^{4} + 14 x^{3} + 77 x^{2} + 200 x + 208 = 0

3 x^{2} - 4 x + 2 = x^{3} - x

2.5 x^{4} + 3 x^{3} - 2.6 x^{2} - 5.1 x - 5.6

What are the solutions to the equation x^4-x^3-2x-4=0 ?
The solutions to the equation x^4-x^3-2x-4=0 are x=-1,x=2,x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of x^4-x^3-2x-4=0
The zeros of x^4-x^3-2x-4=0 are x=-1,x=2,x=sqrt(2)i,x=-sqrt(2)i