What are the solutions to the equation 5x^3+x^2-20x-4=0 ?

The solutions to the equation 5x^3+x^2-20x-4=0 are x=-1/5 ,x=-2,x=2

Find the zeros of 5x^3+x^2-20x-4=0

The zeros of 5x^3+x^2-20x-4=0 are x=-1/5 ,x=-2,x=2

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5 x^{3} + x^{2} - 20 x - 4 = 0

x = - \frac{1}{5}, x = - 2, x = 2

Decimal

x = - 0.2, x = - 2, x = 2

Solution steps

5 x^{3} + x^{2} - 20 x - 4 = 0

Factor

5 x^{3} + x^{2} - 20 x - 4 : (5 x + 1) (x + 2) (x - 2)

(5 x + 1) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x + 1 = 0 or x + 2 = 0 or x - 2 = 0

Solve

5 x + 1 = 0 : x = - \frac{1}{5}

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - \frac{1}{5}, x = - 2, x = 2

10 x^{4} - 20 x^{3} - 30 x^{2} = 0

6 x^{2} - 2 x^{3} = 0

x^{3} - 5 x^{2} - 9 x + 45 = 0

x^{4} + 170 x^{2} + 169 = 0

2 x^{3} - 6 x^{2} + 4 = 0

What are the solutions to the equation 5x^3+x^2-20x-4=0 ?
The solutions to the equation 5x^3+x^2-20x-4=0 are x=-1/5 ,x=-2,x=2
Find the zeros of 5x^3+x^2-20x-4=0
The zeros of 5x^3+x^2-20x-4=0 are x=-1/5 ,x=-2,x=2