What are the solutions to the equation x^3-5x^2-13x-7=0 ?

The solutions to the equation x^3-5x^2-13x-7=0 are x=-1,x=7

Find the zeros of x^3-5x^2-13x-7=0

The zeros of x^3-5x^2-13x-7=0 are x=-1,x=7

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x^{3} - 5 x^{2} - 13 x - 7 = 0

x = - 1, x = 7

Solution steps

x^{3} - 5 x^{2} - 13 x - 7 = 0

Factor

x^{3} - 5 x^{2} - 13 x - 7 : (x + 1)^{2} (x - 7)

(x + 1)^{2} (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 7 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 7 = 0 : x = 7

The solutions are

x = - 1, x = 7

y, x = - y^{3} + 1

- 66 + 6 x^{2} + x^{3} - 11 x = 0

z^{3} = 3 + i

x^{4} + 12 x^{3} + 10 x^{2} - 9 x + 22 = 0

- \frac{1}{8} x^{4} + \frac{5}{2} x^{2} - 8 = 0

What are the solutions to the equation x^3-5x^2-13x-7=0 ?
The solutions to the equation x^3-5x^2-13x-7=0 are x=-1,x=7
Find the zeros of x^3-5x^2-13x-7=0
The zeros of x^3-5x^2-13x-7=0 are x=-1,x=7