What are the solutions to the equation roots x^3-3x^2-4x+12 ?

The solutions to the equation roots x^3-3x^2-4x+12 are x=3,x=-2,x=2

Find the zeros of roots x^3-3x^2-4x+12

The zeros of roots x^3-3x^2-4x+12 are x=3,x=-2,x=2

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roots

x^{3} - 3 x^{2} - 4 x + 12

x = 3, x = - 2, x = 2

Solution steps

x^{3} - 3 x^{2} - 4 x + 12

The roots are the intercepts with the x-axis

(y = 0)

x^{3} - 3 x^{2} - 4 x + 12 = 0

Factor

x^{3} - 3 x^{2} - 4 x + 12 : (x - 3) (x + 2) (x - 2)

(x - 3) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 3, x = - 2, x = 2

2 x^{3} - 3 x^{2} - 32 x + 48 = 0

x^{5} = x

x^{5} - 2 x^{4} + 5 x^{3} - 8 x^{2} + 4 x = 0

8 x^{7} - 56 x^{6} = 0

x^{4} + 6 x^{3} + 18 x^{2} + 30 x + 25 = 0

What are the solutions to the equation roots x^3-3x^2-4x+12 ?
The solutions to the equation roots x^3-3x^2-4x+12 are x=3,x=-2,x=2
Find the zeros of roots x^3-3x^2-4x+12
The zeros of roots x^3-3x^2-4x+12 are x=3,x=-2,x=2