What are the solutions to the equation x^3+7x^2+4x-12=0 ?

The solutions to the equation x^3+7x^2+4x-12=0 are x=1,x=-2,x=-6

Find the zeros of x^3+7x^2+4x-12=0

The zeros of x^3+7x^2+4x-12=0 are x=1,x=-2,x=-6

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x^{3} + 7 x^{2} + 4 x - 12 = 0

x = 1, x = - 2, x = - 6

Solution steps

x^{3} + 7 x^{2} + 4 x - 12 = 0

Factor

x^{3} + 7 x^{2} + 4 x - 12 : (x - 1) (x + 2) (x + 6)

(x - 1) (x + 2) (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0 or x + 6 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

Solve

x + 6 = 0 : x = - 6

The solutions are

x = 1, x = - 2, x = - 6

x^{5} - 5 x^{3} = 36 x

x^{4} - 8 x^{3} + 16 x^{2} = 0

x^{3} - 17 x - 4 = 0

2 x^{4} - 3 x^{3} - 4 x^{2} + 3 x + 2 = 0

2 x^{3} + (- 7) x^{2} + 6 x + 5 = 0

What are the solutions to the equation x^3+7x^2+4x-12=0 ?
The solutions to the equation x^3+7x^2+4x-12=0 are x=1,x=-2,x=-6
Find the zeros of x^3+7x^2+4x-12=0
The zeros of x^3+7x^2+4x-12=0 are x=1,x=-2,x=-6