What is 1/(x+2)+1/(x+3)<= 0 ?

The solution to 1/(x+2)+1/(x+3)<= 0 is x<-3\lor-5/2 <= x<-2

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1/(x+2)+1/(x+3)<= 0

\frac{1}{x + 2} + \frac{1}{x + 3} \leq 0

x < - 3 or - \frac{5}{2} \leq x < - 2

Interval Notation

(- \infty, - 3) \cup [- \frac{5}{2}, - 2)

Decimal Notation

x < - 3 or - 2.5 \leq x < - 2

Solution steps

\frac{1}{x + 2} + \frac{1}{x + 3} \leq 0

Rewrite in standard form

\frac{2 x + 5}{( x + 2 ) ( x + 3 )} \leq 0

Identify the intervals

x < - 3 or - \frac{5}{2} \leq x < - 2

3 x^{2} + 36 = 0

7^{2} + x^{2} = 1 0^{2}

x^{2} - x < 20

2 \leq x < 3

4 x^{2} y + 16 x^{2} - 16 x^{4} y

What is 1/(x+2)+1/(x+3)<= 0 ?
The solution to 1/(x+2)+1/(x+3)<= 0 is x<-3\lor-5/2 <= x<-2