What are the solutions to the equation 2x^3+7x^2-2x-7=0 ?

The solutions to the equation 2x^3+7x^2-2x-7=0 are x=-7/2 ,x=-1,x=1

Find the zeros of 2x^3+7x^2-2x-7=0

The zeros of 2x^3+7x^2-2x-7=0 are x=-7/2 ,x=-1,x=1

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2 x^{3} + 7 x^{2} - 2 x - 7 = 0

x = - \frac{7}{2}, x = - 1, x = 1

Decimal Notation

x = - 3.5, x = - 1, x = 1

Solution steps

2 x^{3} + 7 x^{2} - 2 x - 7 = 0

Factor

2 x^{3} + 7 x^{2} - 2 x - 7 : (2 x + 7) (x + 1) (x - 1)

(2 x + 7) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 7 = 0 or x + 1 = 0 or x - 1 = 0

Solve

2 x + 7 = 0 : x = - \frac{7}{2}

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = - \frac{7}{2}, x = - 1, x = 1

4 x^{3} - 6 x^{2} - 1 = 0

x^{3} + x^{2} - 6 = 0

2 x^{4} - x^{3} - 3 x - 18 = 0

x^{13} + x + 90 = 0

x^{5} - 5 x^{3} - 36 x = 0

What are the solutions to the equation 2x^3+7x^2-2x-7=0 ?
The solutions to the equation 2x^3+7x^2-2x-7=0 are x=-7/2 ,x=-1,x=1
Find the zeros of 2x^3+7x^2-2x-7=0
The zeros of 2x^3+7x^2-2x-7=0 are x=-7/2 ,x=-1,x=1