What are the solutions to the equation x^3-4x^2+5x=0 ?

The solutions to the equation x^3-4x^2+5x=0 are x=0,x=2+i,x=2-i

Find the zeros of x^3-4x^2+5x=0

The zeros of x^3-4x^2+5x=0 are x=0,x=2+i,x=2-i

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x^{3} - 4 x^{2} + 5 x = 0

x = 0, x = 2 + i, x = 2 - i

Solution steps

x^{3} - 4 x^{2} + 5 x = 0

Factor

x^{3} - 4 x^{2} + 5 x : x (x^{2} - 4 x + 5)

x (x^{2} - 4 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} - 4 x + 5 = 0

Solve

x^{2} - 4 x + 5 = 0 : x = 2 + i, x = 2 - i

The solutions are

x = 0, x = 2 + i, x = 2 - i

x^{6} + 18 x^{3} + 81

x^{4} - 2 x^{3} + 3 x^{2} - 2 x + 1 = 0

x^{1} x^{2} = 4 + (- \frac{8}{6})

x^{3} + 2 x^{2} - 5 x - 6

x^{3} - 54 x^{2} + 51 x + 106

What are the solutions to the equation x^3-4x^2+5x=0 ?
The solutions to the equation x^3-4x^2+5x=0 are x=0,x=2+i,x=2-i
Find the zeros of x^3-4x^2+5x=0
The zeros of x^3-4x^2+5x=0 are x=0,x=2+i,x=2-i