What are the solutions to the equation factor x^4-16x^2+75=2x^2-6 ?

The solutions to the equation factor x^4-16x^2+75=2x^2-6 are x=-3,x=3

Find the zeros of factor x^4-16x^2+75=2x^2-6

The zeros of factor x^4-16x^2+75=2x^2-6 are x=-3,x=3

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factor

x^{4} - 16 x^{2} + 75 = 2 x^{2} - 6

x = - 3, x = 3

Solution steps

x^{4} - 16 x^{2} + 75 = 2 x^{2} - 6

Move

6

to the left side

x^{4} - 16 x^{2} + 81 = 2 x^{2}

Move

2 x^{2}

to the left side

x^{4} - 18 x^{2} + 81 = 0

Factor

x^{4} - 18 x^{2} + 81 : (x + 3)^{2} (x - 3)^{2}

(x + 3)^{2} (x - 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 3 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 3, x = 3

m^{3} - 4 m^{2} - 5 m = 0

2 x^{3} + x - 6 = 0

y, 2 x y - x^{3} = 0

2 x^{3} + x - 7 = 0

x^{3} + 8 x^{2} + 16 x = 0

What are the solutions to the equation factor x^4-16x^2+75=2x^2-6 ?
The solutions to the equation factor x^4-16x^2+75=2x^2-6 are x=-3,x=3
Find the zeros of factor x^4-16x^2+75=2x^2-6
The zeros of factor x^4-16x^2+75=2x^2-6 are x=-3,x=3