What are the solutions to the equation y^3-y^2-y+1=0 ?

The solutions to the equation y^3-y^2-y+1=0 are y=1,y=-1

Find the zeros of y^3-y^2-y+1=0

The zeros of y^3-y^2-y+1=0 are y=1,y=-1

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y^{3} - y^{2} - y + 1 = 0

y = 1, y = - 1

Solution steps

y^{3} - y^{2} - y + 1 = 0

Factor

y^{3} - y^{2} - y + 1 : (y - 1)^{2} (y + 1)

(y - 1)^{2} (y + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y - 1 = 0 or y + 1 = 0

Solve

y - 1 = 0 : y = 1

Solve

y + 1 = 0 : y = - 1

The solutions are

y = 1, y = - 1

x^{4} + 26 x^{2} + 25 = 0

0 = 4 x^{3} + 2 x - 12

64 x = x^{4}

6 x^{3} - 11 x^{2} - 9 x - 1 = 0

30 x^{4} - 120 x^{3} = 0

What are the solutions to the equation y^3-y^2-y+1=0 ?
The solutions to the equation y^3-y^2-y+1=0 are y=1,y=-1
Find the zeros of y^3-y^2-y+1=0
The zeros of y^3-y^2-y+1=0 are y=1,y=-1