What are the solutions to the equation x^2(x-9)(2x+1)=0 ?

The solutions to the equation x^2(x-9)(2x+1)=0 are x=0,x=9,x=-1/2

Find the zeros of x^2(x-9)(2x+1)=0

The zeros of x^2(x-9)(2x+1)=0 are x=0,x=9,x=-1/2

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x^{2} (x - 9) (2 x + 1) = 0

x = 0, x = 9, x = - \frac{1}{2}

Decimal Notation

x = 0, x = 9, x = - 0.5

Solution steps

x^{2} (x - 9) (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 9 = 0 or 2 x + 1 = 0

Solve

x - 9 = 0 : x = 9

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions are

x = 0, x = 9, x = - \frac{1}{2}

\frac{1}{4} r^{4} + r^{2} - 80 = 0

x^{4} = \frac{1}{81}

k^{3} - 9 k^{2} + 8 k + 60 = 0

x^{3} + 2 x^{2} - 5 x + 6 = 0

x^{3} + 2 x^{2} - 5 x - 10 = 0

What are the solutions to the equation x^2(x-9)(2x+1)=0 ?
The solutions to the equation x^2(x-9)(2x+1)=0 are x=0,x=9,x=-1/2
Find the zeros of x^2(x-9)(2x+1)=0
The zeros of x^2(x-9)(2x+1)=0 are x=0,x=9,x=-1/2