What are the solutions to the equation roots x^4-5x^2+4=0 ?

The solutions to the equation roots x^4-5x^2+4=0 are x=2,x=-2,x=1,x=-1

Find the zeros of roots x^4-5x^2+4=0

The zeros of roots x^4-5x^2+4=0 are x=2,x=-2,x=1,x=-1

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roots

x^{4} - 5 x^{2} + 4 = 0

x = 2, x = - 2, x = 1, x = - 1

Solution steps

x^{4} - 5 x^{2} + 4 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} - 5 u + 4 = 0

Solve

u^{2} - 5 u + 4 = 0 : u = 4, u = 1

u = 4, u = 1

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 4 : x = 2, x = - 2

Solve

x^{2} = 1 : x = 1, x = - 1

The solutions are

x = 2, x = - 2, x = 1, x = - 1

2 x^{3} + 2 x^{2} + 1 = 0

12 x - 6 x^{2} + 3 x^{4} = 6 x^{3} + 2 x - x^{4}

4 x^{3} + 56 x^{2} + 132 x = 0

125 t^{10} - 3 t^{7} = 0

- 3 x^{3} + 40 x^{2} - 90 x + 150 = 0

What are the solutions to the equation roots x^4-5x^2+4=0 ?
The solutions to the equation roots x^4-5x^2+4=0 are x=2,x=-2,x=1,x=-1
Find the zeros of roots x^4-5x^2+4=0
The zeros of roots x^4-5x^2+4=0 are x=2,x=-2,x=1,x=-1