What are the solutions to the equation x^3+13x^2+40x+36=0 ?

The solutions to the equation x^3+13x^2+40x+36=0 are x=-2,x=-9

Find the zeros of x^3+13x^2+40x+36=0

The zeros of x^3+13x^2+40x+36=0 are x=-2,x=-9

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x^{3} + 13 x^{2} + 40 x + 36 = 0

x = - 2, x = - 9

Solution steps

x^{3} + 13 x^{2} + 40 x + 36 = 0

Factor

x^{3} + 13 x^{2} + 40 x + 36 : (x + 2)^{2} (x + 9)

(x + 2)^{2} (x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 9 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 9 = 0 : x = - 9

The solutions are

x = - 2, x = - 9

3 x^{3} + 5 x^{2} + 10 x - 4 = 0

90 x^{8} (1 - x) = 0.75

36 x^{3} + 45 x^{2} - 7 x - 4 = 0

x^{5} + 3 x - 4 = 0

z^{6} - z^{3} - 2 = 0

What are the solutions to the equation x^3+13x^2+40x+36=0 ?
The solutions to the equation x^3+13x^2+40x+36=0 are x=-2,x=-9
Find the zeros of x^3+13x^2+40x+36=0
The zeros of x^3+13x^2+40x+36=0 are x=-2,x=-9