What are the solutions to the equation x(x^2+4)=0 ?

The solutions to the equation x(x^2+4)=0 are x=0,x=2i,x=-2i

Find the zeros of x(x^2+4)=0

The zeros of x(x^2+4)=0 are x=0,x=2i,x=-2i

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x (x^{2} + 4) = 0

x = 0, x = 2 i, x = - 2 i

Solution steps

x (x^{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 4 = 0

Solve

x^{2} + 4 = 0 : x = 2 i, x = - 2 i

The solutions are

x = 0, x = 2 i, x = - 2 i

m^{3} + 4 m = 0

r^{4} + r^{3} - 7 r^{2} - r + 6 = 0

4 x - 4 x^{9} = 0

y, (x^{2} + y^{2})^{2} = x^{2} - y^{2}

81 = x^{4}

What are the solutions to the equation x(x^2+4)=0 ?
The solutions to the equation x(x^2+4)=0 are x=0,x=2i,x=-2i
Find the zeros of x(x^2+4)=0
The zeros of x(x^2+4)=0 are x=0,x=2i,x=-2i