What are the solutions to the equation roots x^3-x^2-x+1=0 ?

The solutions to the equation roots x^3-x^2-x+1=0 are x=1,x=-1

Find the zeros of roots x^3-x^2-x+1=0

The zeros of roots x^3-x^2-x+1=0 are x=1,x=-1

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roots

x^{3} - x^{2} - x + 1 = 0

x = 1, x = - 1

Solution steps

x^{3} - x^{2} - x + 1 = 0

Factor

x^{3} - x^{2} - x + 1 : (x - 1)^{2} (x + 1)

(x - 1)^{2} (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 1 = 0 : x = - 1

The solutions are

x = 1, x = - 1

2 x^{4} = 48 x^{2}

2 x^{4} + 16 x^{3} + 32 x^{2} = 0

x^{4} - x^{2} = 12

3 q (q + 6) 2 (q + 6) = 0

3 x^{5} - 8 x^{4} + 2 x^{3} + 5 x^{2} - 2 x + 1 = 0

What are the solutions to the equation roots x^3-x^2-x+1=0 ?
The solutions to the equation roots x^3-x^2-x+1=0 are x=1,x=-1
Find the zeros of roots x^3-x^2-x+1=0
The zeros of roots x^3-x^2-x+1=0 are x=1,x=-1