What are the solutions to the equation x^4+9x^3+23x^2+3x-36=0 ?

The solutions to the equation x^4+9x^3+23x^2+3x-36=0 are x=1,x=-3,x=-4

Find the zeros of x^4+9x^3+23x^2+3x-36=0

The zeros of x^4+9x^3+23x^2+3x-36=0 are x=1,x=-3,x=-4

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x^{4} + 9 x^{3} + 23 x^{2} + 3 x - 36 = 0

x = 1, x = - 3, x = - 4

Solution steps

x^{4} + 9 x^{3} + 23 x^{2} + 3 x - 36 = 0

Factor

x^{4} + 9 x^{3} + 23 x^{2} + 3 x - 36 : (x - 1) (x + 3)^{2} (x + 4)

(x - 1) (x + 3)^{2} (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 3 = 0 or x + 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 3 = 0 : x = - 3

Solve

x + 4 = 0 : x = - 4

The solutions are

x = 1, x = - 3, x = - 4

6 x^{5} + 11 x^{4} - 39 x^{3} - 41 x^{2} + 45 x + 18 = 0

5 x^{3} = 320

x^{3} - 5 x^{2} - 4 x + 20

x^{3} - 2 x^{2} + x - 2

x, (x^{2} + y)^{3} = y

What are the solutions to the equation x^4+9x^3+23x^2+3x-36=0 ?
The solutions to the equation x^4+9x^3+23x^2+3x-36=0 are x=1,x=-3,x=-4
Find the zeros of x^4+9x^3+23x^2+3x-36=0
The zeros of x^4+9x^3+23x^2+3x-36=0 are x=1,x=-3,x=-4