What are the solutions to the equation 2x^3-3x^2+4x-6=0 ?

The solutions to the equation 2x^3-3x^2+4x-6=0 are x= 3/2 ,x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of 2x^3-3x^2+4x-6=0

The zeros of 2x^3-3x^2+4x-6=0 are x= 3/2 ,x=sqrt(2)i,x=-sqrt(2)i

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2 x^{3} - 3 x^{2} + 4 x - 6 = 0

x = \frac{3}{2}, x = 2 i, x = - 2 i

Solution steps

2 x^{3} - 3 x^{2} + 4 x - 6 = 0

Factor

2 x^{3} - 3 x^{2} + 4 x - 6 : (2 x - 3) (x^{2} + 2)

(2 x - 3) (x^{2} + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 3 = 0 or x^{2} + 2 = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

x^{2} + 2 = 0 : x = 2 i, x = - 2 i

The solutions are

x = \frac{3}{2}, x = 2 i, x = - 2 i

x^{6} + x^{3} + 1

32 xxx - 234 xx + 410 x - 39 = 0

x^{3} - 6 x^{2} + 11 x - 6 = 0

z^{5} - z = 0

1 + z^{4} = 0

What are the solutions to the equation 2x^3-3x^2+4x-6=0 ?
The solutions to the equation 2x^3-3x^2+4x-6=0 are x= 3/2 ,x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of 2x^3-3x^2+4x-6=0
The zeros of 2x^3-3x^2+4x-6=0 are x= 3/2 ,x=sqrt(2)i,x=-sqrt(2)i