What are the solutions to the equation x^3-12x+2=0 ?

The solutions to the equation x^3-12x+2=0 are x\approx 0.16705…,x\approx 3.37755…,x\approx-3.54460…

Find the zeros of x^3-12x+2=0

The zeros of x^3-12x+2=0 are x\approx 0.16705…,x\approx 3.37755…,x\approx-3.54460…

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x^{3} - 12 x + 2 = 0

x \approx 0.16705 \dots, x \approx 3.37755 \dots, x \approx - 3.54460 \dots

Solution steps

x^{3} - 12 x + 2 = 0

Find one solution for

x^{3} - 12 x + 2 = 0

using Newton-Raphson:

x \approx 0.16705 \dots

Apply long division:

\frac{x ^{3} - 12 x + 2}{x - 0.16705 \dots} = x^{2} + 0.16705 \dots x - 11.97209 \dots

x^{2} + 0.16705 \dots x - 11.97209 \dots \approx 0

Find one solution for

x^{2} + 0.16705 \dots x - 11.97209 \dots = 0

using Newton-Raphson:

x \approx 3.37755 \dots

Apply long division:

\frac{x ^{2} + 0.16705 \dots x - 11.97209 \dots}{x - 3.37755 \dots} = x + 3.54460 \dots

x + 3.54460 \dots \approx 0

x \approx - 3.54460 \dots

The solutions are

x \approx 0.16705 \dots, x \approx 3.37755 \dots, x \approx - 3.54460 \dots

- m^{4} + 3 m^{2} + 2 m = 0

2 x^{3} - 4 x^{2} + 2 x - 2 = 0

x^{3} + x^{2} - 150 = 0

x^{4} - 4 x^{2} + 1

6 x^{3} - 15 x^{2} - 12 x + 5 = 0

What are the solutions to the equation x^3-12x+2=0 ?
The solutions to the equation x^3-12x+2=0 are x\approx 0.16705…,x\approx 3.37755…,x\approx-3.54460…
Find the zeros of x^3-12x+2=0
The zeros of x^3-12x+2=0 are x\approx 0.16705…,x\approx 3.37755…,x\approx-3.54460…