What are the solutions to the equation 4x^3-6x^2+2=0 ?

The solutions to the equation 4x^3-6x^2+2=0 are x=1,x=-1/2

Find the zeros of 4x^3-6x^2+2=0

The zeros of 4x^3-6x^2+2=0 are x=1,x=-1/2

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4 x^{3} - 6 x^{2} + 2 = 0

x = 1, x = - \frac{1}{2}

Decimal Notation

x = 1, x = - 0.5

Solution steps

4 x^{3} - 6 x^{2} + 2 = 0

Factor

4 x^{3} - 6 x^{2} + 2 : 2 (x - 1)^{2} (2 x + 1)

2 (x - 1)^{2} (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x + 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions are

x = 1, x = - \frac{1}{2}

4 z^{4} - 5 i z^{2} + 1 = 0

x^{3} - 13 x^{2} + 59 x - 87 = 0

y, 2 x^{3} = 2 y^{2} + 5

x^{4} - 13 x^{2} - 12 x = 0

x^{4} - 200 x^{3} - 100 x^{2} = 0

What are the solutions to the equation 4x^3-6x^2+2=0 ?
The solutions to the equation 4x^3-6x^2+2=0 are x=1,x=-1/2
Find the zeros of 4x^3-6x^2+2=0
The zeros of 4x^3-6x^2+2=0 are x=1,x=-1/2