What are the solutions to the equation (25-x^2)^2=0 ?

The solutions to the equation (25-x^2)^2=0 are x=5,x=-5

Find the zeros of (25-x^2)^2=0

The zeros of (25-x^2)^2=0 are x=5,x=-5

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(25 - x^{2})^{2} = 0

x = 5, x = - 5

Solution steps

(25 - x^{2})^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

25 - x^{2} = 0 : x = 5, x = - 5

The solutions are

x = 5, x = - 5

27 x^{3} - (x - 1)^{3} = 0

x^{4} - 4 x^{2} - 1 = 0

240 x^{3} + 720 x^{2} - 600 x = 0

z^{3} = (3 + i)

x^{3} - 3 x^{2} - 10 x = - 24

What are the solutions to the equation (25-x^2)^2=0 ?
The solutions to the equation (25-x^2)^2=0 are x=5,x=-5
Find the zeros of (25-x^2)^2=0
The zeros of (25-x^2)^2=0 are x=5,x=-5