What is the answer to solvefor y,x^2+3x^4y=4 ?

The answer to solvefor y,x^2+3x^4y=4 is y=(4-x^2)/(3x^4);\quad x\ne 0

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solvefor y,x^2+3x^4y=4

solve for

y, x^{2} + 3 x^{4} y = 4

y = \frac{4 - x ^{2}}{3 x ^{4}}; x \neq = 0

Solution steps

x^{2} + 3 x^{4} y = 4

Move

x^{2}

to the right side

3 x^{4} y = 4 - x^{2}

Divide both sides by

3 x^{4}; x \neq = 0

y = \frac{4 - x ^{2}}{3 x ^{4}}; x \neq = 0

2 x^{5} + 3 x^{4} - 2 x - 3

15 x^{4} - 12 x^{2} - 3 = 0

x^{4} + 25 = 26 x^{2}

2 x^{3} - 3 x^{2} - 11 x + 6

x^{4} = 5 x + 6

What is the answer to solvefor y,x^2+3x^4y=4 ?
The answer to solvefor y,x^2+3x^4y=4 is y=(4-x^2)/(3x^4);\quad x\ne 0