What are the solutions to the equation x^2-1.6x+0.6=0 ?

The solutions to the equation x^2-1.6x+0.6=0 are x=1,x= 3/5

Find the zeros of x^2-1.6x+0.6=0

The zeros of x^2-1.6x+0.6=0 are x=1,x= 3/5

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x^{2} - 1.6 x + 0.6 = 0

x = 1, x = \frac{3}{5}

Decimal Notation

x = 1, x = 0.6

Solution steps

x^{2} - 1.6 x + 0.6 = 0

Multiply both sides by

10

10 x^{2} - 16 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 10 \cdot 6}{2 \cdot 10}

(- 16)^{2} - 4 \cdot 10 \cdot 6 = 4

x_{1, 2} = \frac{- ( - 16 ) \pm 4}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4}{2 \cdot 10}, x_{2} = \frac{- ( - 16 ) - 4}{2 \cdot 10}

x = \frac{- ( - 16 ) + 4}{2 \cdot 10} : 1

x = \frac{- ( - 16 ) - 4}{2 \cdot 10} : \frac{3}{5}

The solutions to the quadratic equation are:

x = 1, x = \frac{3}{5}

y^{2} + 8 y + 15

\frac{4}{6} - (- \frac{1}{6})

y^{2} + 2 y + 1

x - 1 < 8

t = 2 π \frac{3.2}{980}

What are the solutions to the equation x^2-1.6x+0.6=0 ?
The solutions to the equation x^2-1.6x+0.6=0 are x=1,x= 3/5
Find the zeros of x^2-1.6x+0.6=0
The zeros of x^2-1.6x+0.6=0 are x=1,x= 3/5