What are the solutions to the equation 240x^3+360x^2-1800x=0 ?

The solutions to the equation 240x^3+360x^2-1800x=0 are x=0,x=(-3+sqrt(129))/4 ,x=(-3-sqrt(129))/4

Find the zeros of 240x^3+360x^2-1800x=0

The zeros of 240x^3+360x^2-1800x=0 are x=0,x=(-3+sqrt(129))/4 ,x=(-3-sqrt(129))/4

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240 x^{3} + 360 x^{2} - 1800 x = 0

x = 0, x = \frac{- 3 + 129}{4}, x = \frac{- 3 - 129}{4}

Decimal Notation

x = 0, x = 2.08945 \dots, x = - 3.58945 \dots

Solution steps

240 x^{3} + 360 x^{2} - 1800 x = 0

Factor

240 x^{3} + 360 x^{2} - 1800 x : 120 x (2 x^{2} + 3 x - 15)

120 x (2 x^{2} + 3 x - 15) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x^{2} + 3 x - 15 = 0

Solve

2 x^{2} + 3 x - 15 = 0 : x = \frac{- 3 + 129}{4}, x = \frac{- 3 - 129}{4}

The solutions are

x = 0, x = \frac{- 3 + 129}{4}, x = \frac{- 3 - 129}{4}

x^{3} - 2 x^{2} + 9 x - 18

125 = 40 x \frac{1}{2} (10) x^{2}

x^{4} - 8 x^{3} + 26 x^{2} - 40 x + 25 = 0

2 x^{3} + x - 4 = 0

- 3 z^{3} + 140 - 139 z + 38 z^{2} = 0

What are the solutions to the equation 240x^3+360x^2-1800x=0 ?
The solutions to the equation 240x^3+360x^2-1800x=0 are x=0,x=(-3+sqrt(129))/4 ,x=(-3-sqrt(129))/4
Find the zeros of 240x^3+360x^2-1800x=0
The zeros of 240x^3+360x^2-1800x=0 are x=0,x=(-3+sqrt(129))/4 ,x=(-3-sqrt(129))/4