What are the solutions to the equation roots x^3-4x^2-x+4 ?

The solutions to the equation roots x^3-4x^2-x+4 are x=4,x=-1,x=1

Find the zeros of roots x^3-4x^2-x+4

The zeros of roots x^3-4x^2-x+4 are x=4,x=-1,x=1

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roots

x^{3} - 4 x^{2} - x + 4

x = 4, x = - 1, x = 1

Solution steps

x^{3} - 4 x^{2} - x + 4

The roots are the intercepts with the x-axis

(y = 0)

x^{3} - 4 x^{2} - x + 4 = 0

Factor

x^{3} - 4 x^{2} - x + 4 : (x - 4) (x + 1) (x - 1)

(x - 4) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x - 4 = 0 : x = 4

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = 4, x = - 1, x = 1

2 x^{3} + x - 5 = 0

2 x^{3} + 6 x - 1 = 0

x^{4} - 4 x^{3} - x + 2 = 0

w^{4} + 36 = 13 w^{2}

2 x^{3} - 8 x + 15 x = 18

What are the solutions to the equation roots x^3-4x^2-x+4 ?
The solutions to the equation roots x^3-4x^2-x+4 are x=4,x=-1,x=1
Find the zeros of roots x^3-4x^2-x+4
The zeros of roots x^3-4x^2-x+4 are x=4,x=-1,x=1