What are the solutions to the equation 5x^3+29x^2+19x-5=0 ?

The solutions to the equation 5x^3+29x^2+19x-5=0 are x=-1,x= 1/5 ,x=-5

Find the zeros of 5x^3+29x^2+19x-5=0

The zeros of 5x^3+29x^2+19x-5=0 are x=-1,x= 1/5 ,x=-5

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5 x^{3} + 29 x^{2} + 19 x - 5 = 0

x = - 1, x = \frac{1}{5}, x = - 5

Decimal Notation

x = - 1, x = 0.2, x = - 5

Solution steps

5 x^{3} + 29 x^{2} + 19 x - 5 = 0

Factor

5 x^{3} + 29 x^{2} + 19 x - 5 : (x + 1) (5 x - 1) (x + 5)

(x + 1) (5 x - 1) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 5 x - 1 = 0 or x + 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

5 x - 1 = 0 : x = \frac{1}{5}

Solve

x + 5 = 0 : x = - 5

The solutions are

x = - 1, x = \frac{1}{5}, x = - 5

x^{3} + x - 130 = 0

x^{3} - 125

8 x^{4} + 10 x^{3} + 9 x^{2} + x - 1 = 0

x^{4} + 3 x^{2} + 2 x + 14 = 0

4 x^{4} - 22 x^{3} + 38 x^{2} - 44 x + 60 = 0

What are the solutions to the equation 5x^3+29x^2+19x-5=0 ?
The solutions to the equation 5x^3+29x^2+19x-5=0 are x=-1,x= 1/5 ,x=-5
Find the zeros of 5x^3+29x^2+19x-5=0
The zeros of 5x^3+29x^2+19x-5=0 are x=-1,x= 1/5 ,x=-5