What are the solutions to the equation x^3+3x^2-18x-40=0 ?

The solutions to the equation x^3+3x^2-18x-40=0 are x=-2,x=4,x=-5

Find the zeros of x^3+3x^2-18x-40=0

The zeros of x^3+3x^2-18x-40=0 are x=-2,x=4,x=-5

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x^{3} + 3 x^{2} - 18 x - 40 = 0

x = - 2, x = 4, x = - 5

Solution steps

x^{3} + 3 x^{2} - 18 x - 40 = 0

Factor

x^{3} + 3 x^{2} - 18 x - 40 : (x + 2) (x - 4) (x + 5)

(x + 2) (x - 4) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 4 = 0 or x + 5 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 4 = 0 : x = 4

Solve

x + 5 = 0 : x = - 5

The solutions are

x = - 2, x = 4, x = - 5

y, 25 x^{4} - 625 y - 500 = 0

x^{4} + 2 x^{2} - x + 8

101 x^{100} + 51 x^{50} + 1 = 0

x^{4} - 4 x^{2} = x^{2} - 4

5 x^{4} - 3 x^{2} = 0

What are the solutions to the equation x^3+3x^2-18x-40=0 ?
The solutions to the equation x^3+3x^2-18x-40=0 are x=-2,x=4,x=-5
Find the zeros of x^3+3x^2-18x-40=0
The zeros of x^3+3x^2-18x-40=0 are x=-2,x=4,x=-5