What are the solutions to the equation x^3+5x^2+24x+20=0 ?

The solutions to the equation x^3+5x^2+24x+20=0 are x=-1,x=-2+4i,x=-2-4i

Find the zeros of x^3+5x^2+24x+20=0

The zeros of x^3+5x^2+24x+20=0 are x=-1,x=-2+4i,x=-2-4i

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x^{3} + 5 x^{2} + 24 x + 20 = 0

x = - 1, x = - 2 + 4 i, x = - 2 - 4 i

Solution steps

x^{3} + 5 x^{2} + 24 x + 20 = 0

Factor

x^{3} + 5 x^{2} + 24 x + 20 : (x + 1) (x^{2} + 4 x + 20)

(x + 1) (x^{2} + 4 x + 20) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{2} + 4 x + 20 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{2} + 4 x + 20 = 0 : x = - 2 + 4 i, x = - 2 - 4 i

The solutions are

x = - 1, x = - 2 + 4 i, x = - 2 - 4 i

3 x^{2} (x - 1) - 2 = x^{2}

x^{4} + 4 x^{3} - 5 x^{2} - 16 x + 4 = 0

3 x^{5} + x^{4} - 9 x^{3} - 9 x^{2} - 2 x = 0

x + x^{3} = 4

x^{3} + 125 = 0

What are the solutions to the equation x^3+5x^2+24x+20=0 ?
The solutions to the equation x^3+5x^2+24x+20=0 are x=-1,x=-2+4i,x=-2-4i
Find the zeros of x^3+5x^2+24x+20=0
The zeros of x^3+5x^2+24x+20=0 are x=-1,x=-2+4i,x=-2-4i