What are the solutions to the equation 6x^4+8x^3=0 ?

The solutions to the equation 6x^4+8x^3=0 are x=0,x=-4/3

Find the zeros of 6x^4+8x^3=0

The zeros of 6x^4+8x^3=0 are x=0,x=-4/3

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6 x^{4} + 8 x^{3} = 0

x = 0, x = - \frac{4}{3}

Decimal

x = 0, x = - 1.33333 \dots

Solution steps

6 x^{4} + 8 x^{3} = 0

Factor

6 x^{4} + 8 x^{3} : 2 x^{3} (3 x + 4)

2 x^{3} (3 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x + 4 = 0

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

The solutions are

x = 0, x = - \frac{4}{3}

2 x^{3} - 5 x^{2} + 8 x - 5

x^{2} 3 x + 2 = 0

x^{4} + 6 x^{3} + 15 x^{2} + 20 x + 12

2 x^{4} + 5 x^{2} + 3 = 0

- 2 x^{3} + 6 x^{2} + 20 x = 0

What are the solutions to the equation 6x^4+8x^3=0 ?
The solutions to the equation 6x^4+8x^3=0 are x=0,x=-4/3
Find the zeros of 6x^4+8x^3=0
The zeros of 6x^4+8x^3=0 are x=0,x=-4/3