What are the solutions to the equation roots s^3+s^2+4s+4 ?

The solutions to the equation roots s^3+s^2+4s+4 are s=-1,s=2i,s=-2i

Find the zeros of roots s^3+s^2+4s+4

The zeros of roots s^3+s^2+4s+4 are s=-1,s=2i,s=-2i

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roots

s^{3} + s^{2} + 4 s + 4

s = - 1, s = 2 i, s = - 2 i

Solution steps

s^{3} + s^{2} + 4 s + 4

The roots are the intercepts with the x-axis

(y = 0)

s^{3} + s^{2} + 4 s + 4 = 0

Factor

s^{3} + s^{2} + 4 s + 4 : (s + 1) (s^{2} + 4)

(s + 1) (s^{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

s + 1 = 0 or s^{2} + 4 = 0

Solve

s + 1 = 0 : s = - 1

Solve

s^{2} + 4 = 0 : s = 2 i, s = - 2 i

The solutions are

s = - 1, s = 2 i, s = - 2 i

x^{4} + 8 x^{2} + 12 = 0

x^{3} - 4 x^{2} + 4 x - 4 = 0

4 x^{3} - 6 x^{2} + 4 x = 0

x^{4} + 2 x^{3} + x^{2} + 8 x - 12

y, x^{5} + y^{5} = 16

What are the solutions to the equation roots s^3+s^2+4s+4 ?
The solutions to the equation roots s^3+s^2+4s+4 are s=-1,s=2i,s=-2i
Find the zeros of roots s^3+s^2+4s+4
The zeros of roots s^3+s^2+4s+4 are s=-1,s=2i,s=-2i