What are the solutions to the equation 2x^4=24x^2 ?

The solutions to the equation 2x^4=24x^2 are x=0,x=-2sqrt(3),x=2sqrt(3)

Find the zeros of 2x^4=24x^2

The zeros of 2x^4=24x^2 are x=0,x=-2sqrt(3),x=2sqrt(3)

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2 x^{4} = 24 x^{2}

x = 0, x = - 23, x = 23

Decimal Notation

x = 0, x = - 3.46410 \dots, x = 3.46410 \dots

Solution steps

2 x^{4} = 24 x^{2}

Move

24 x^{2}

to the left side

2 x^{4} - 24 x^{2} = 0

Factor

2 x^{4} - 24 x^{2} : 2 x^{2} (x + 23) (x - 23)

2 x^{2} (x + 23) (x - 23) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 23 = 0 or x - 23 = 0

Solve

x + 23 = 0 : x = - 23

Solve

x - 23 = 0 : x = 23

The solutions are

x = 0, x = - 23, x = 23

6 x^{4} + 13 x^{3} - 8 x^{2} - 17 x + 6 = 0

4 x^{4} + 2 x^{2} - 1 = 0

y, y^{2} = x^{2} - x^{4}

2 x^{5} - 2 x^{3} = 0

x^{3} + 5 x^{2} + 9 x + 5

What are the solutions to the equation 2x^4=24x^2 ?
The solutions to the equation 2x^4=24x^2 are x=0,x=-2sqrt(3),x=2sqrt(3)
Find the zeros of 2x^4=24x^2
The zeros of 2x^4=24x^2 are x=0,x=-2sqrt(3),x=2sqrt(3)