What are the solutions to the equation roots x^3+5x^2+7x+3=0 ?

The solutions to the equation roots x^3+5x^2+7x+3=0 are x=-1,x=-3

Find the zeros of roots x^3+5x^2+7x+3=0

The zeros of roots x^3+5x^2+7x+3=0 are x=-1,x=-3

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roots

x^{3} + 5 x^{2} + 7 x + 3 = 0

x = - 1, x = - 3

Solution steps

x^{3} + 5 x^{2} + 7 x + 3 = 0

Factor

x^{3} + 5 x^{2} + 7 x + 3 : (x + 1)^{2} (x + 3)

(x + 1)^{2} (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 3 = 0 : x = - 3

The solutions are

x = - 1, x = - 3

12 x^{4} - 32 x^{3} + 13 x^{2} + 8 x + 1 = 0

a^{3} = 3^{9} \times 1 2^{3} \times 2 1^{6}

x (x^{2} + 2 x + 1) = 2 (x + 1)

y, 2 x^{3} y^{1} = y (2 x^{2} - y^{2})

x^{10} + 6 x^{5} - 16 = 0

What are the solutions to the equation roots x^3+5x^2+7x+3=0 ?
The solutions to the equation roots x^3+5x^2+7x+3=0 are x=-1,x=-3
Find the zeros of roots x^3+5x^2+7x+3=0
The zeros of roots x^3+5x^2+7x+3=0 are x=-1,x=-3