What are the solutions to the equation 0=x^3-7x^2-x+7 ?

The solutions to the equation 0=x^3-7x^2-x+7 are x=7,x=-1,x=1

Find the zeros of 0=x^3-7x^2-x+7

The zeros of 0=x^3-7x^2-x+7 are x=7,x=-1,x=1

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0 = x^{3} - 7 x^{2} - x + 7

x = 7, x = - 1, x = 1

Solution steps

0 = x^{3} - 7 x^{2} - x + 7

Switch sides

x^{3} - 7 x^{2} - x + 7 = 0

Factor

x^{3} - 7 x^{2} - x + 7 : (x - 7) (x + 1) (x - 1)

(x - 7) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 7 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x - 7 = 0 : x = 7

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = 7, x = - 1, x = 1

x^{3} + 2 x^{2} - 40 x + 64 = 0

x^{3} + 3 x^{2} - 4 x - 12 = 0

z^{4} = - 83 + 8 i

2 = \frac{4}{3} π r^{3}

16 x^{4} = 1

What are the solutions to the equation 0=x^3-7x^2-x+7 ?
The solutions to the equation 0=x^3-7x^2-x+7 are x=7,x=-1,x=1
Find the zeros of 0=x^3-7x^2-x+7
The zeros of 0=x^3-7x^2-x+7 are x=7,x=-1,x=1