What are the solutions to the equation factor x^4+2x^2+1=0 ?

The solutions to the equation factor x^4+2x^2+1=0 are x=i,x=-i

Find the zeros of factor x^4+2x^2+1=0

The zeros of factor x^4+2x^2+1=0 are x=i,x=-i

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factor

x^{4} + 2 x^{2} + 1 = 0

x = i, x = - i

Solution steps

x^{4} + 2 x^{2} + 1 = 0

Factor

x^{4} + 2 x^{2} + 1 : (x^{2} + 1)^{2}

(x^{2} + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x^{2} + 1 = 0

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = i, x = - i

x^{4} - x^{3} + 7 x^{2} - 9 x - 18 = 0

3 y^{3} - 11 y^{2} - 4 y = 0

n P^{5}

z^{4} = 4 - i

2 x^{4} - 5 x^{3} - 20 x^{2} + 115 x - 52 = 0

What are the solutions to the equation factor x^4+2x^2+1=0 ?
The solutions to the equation factor x^4+2x^2+1=0 are x=i,x=-i
Find the zeros of factor x^4+2x^2+1=0
The zeros of factor x^4+2x^2+1=0 are x=i,x=-i