What are the solutions to the equation 3(x-2)^2+4=52 ?

The solutions to the equation 3(x-2)^2+4=52 are x=6,x=-2

Find the zeros of 3(x-2)^2+4=52

The zeros of 3(x-2)^2+4=52 are x=6,x=-2

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3 (x - 2)^{2} + 4 = 52

x = 6, x = - 2

Solution steps

3 (x - 2)^{2} + 4 = 52

Move

4

to the right side

3 (x - 2)^{2} = 48

Divide both sides by

3

(x - 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 16 : x = 6

Solve

x - 2 = - 16 : x = - 2

The solutions to the quadratic equation are:

x = 6, x = - 2

\frac{( 1 - x ^{2} )}{x ^{3} - 1}

- 14 - 8 x = - 2 ((- 3 x + 7))

10 x^{2} + 19 x - 15 = 0

\frac{\frac{x}{y} + \frac{y}{x}}{\frac{x}{y} - \frac{y}{x}}

\frac{( 8 m ^{6} n ^{4} ) ^{3}}{4 m ^{3} n ^{2}}

What are the solutions to the equation 3(x-2)^2+4=52 ?
The solutions to the equation 3(x-2)^2+4=52 are x=6,x=-2
Find the zeros of 3(x-2)^2+4=52
The zeros of 3(x-2)^2+4=52 are x=6,x=-2