What are the solutions to the equation 4x^3+12x^2-36x=0 ?

The solutions to the equation 4x^3+12x^2-36x=0 are x=0,x=(-3+3sqrt(5))/2 ,x=(-3-3sqrt(5))/2

Find the zeros of 4x^3+12x^2-36x=0

The zeros of 4x^3+12x^2-36x=0 are x=0,x=(-3+3sqrt(5))/2 ,x=(-3-3sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{3} + 12 x^{2} - 36 x = 0

x = 0, x = \frac{- 3 + 3 5}{2}, x = \frac{- 3 - 3 5}{2}

Decimal Notation

x = 0, x = 1.85410 \dots, x = - 4.85410 \dots

Solution steps

4 x^{3} + 12 x^{2} - 36 x = 0

Factor

4 x^{3} + 12 x^{2} - 36 x : 4 x (x^{2} + 3 x - 9)

4 x (x^{2} + 3 x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 3 x - 9 = 0

Solve

x^{2} + 3 x - 9 = 0 : x = \frac{- 3 + 3 5}{2}, x = \frac{- 3 - 3 5}{2}

The solutions are

x = 0, x = \frac{- 3 + 3 5}{2}, x = \frac{- 3 - 3 5}{2}

x^{5} + x^{15} + x^{25} = 780

9 x^{4} - 42 x^{3} + 64 x^{2} - 35 x + 4 = 0

z^{4} = 4 i

r^{3} - 5 r^{2} + 8 r - 4 = 0

x^{3} - 3 x^{2} + 5 x - 4 = 0

What are the solutions to the equation 4x^3+12x^2-36x=0 ?
The solutions to the equation 4x^3+12x^2-36x=0 are x=0,x=(-3+3sqrt(5))/2 ,x=(-3-3sqrt(5))/2
Find the zeros of 4x^3+12x^2-36x=0
The zeros of 4x^3+12x^2-36x=0 are x=0,x=(-3+3sqrt(5))/2 ,x=(-3-3sqrt(5))/2