What are the solutions to the equation roots x^3-3x^2+x-3 ?

The solutions to the equation roots x^3-3x^2+x-3 are x=3,x=i,x=-i

Find the zeros of roots x^3-3x^2+x-3

The zeros of roots x^3-3x^2+x-3 are x=3,x=i,x=-i

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roots

x^{3} - 3 x^{2} + x - 3

x = 3, x = i, x = - i

Solution steps

x^{3} - 3 x^{2} + x - 3

The roots are the intercepts with the x-axis

(y = 0)

x^{3} - 3 x^{2} + x - 3 = 0

Factor

x^{3} - 3 x^{2} + x - 3 : (x - 3) (x^{2} + 1)

(x - 3) (x^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x^{2} + 1 = 0

Solve

x - 3 = 0 : x = 3

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = 3, x = i, x = - i

2 m^{5} - 7 m^{4} + 12 m^{3} + 8 m^{2} = 0

x^{3} - 2 x^{2} + 3 x = 0

m^{5} - 4 m^{4} + 4 m^{3} = 0

3 x^{6} - 39 x^{4} + 108 x^{2} = 0

16 x^{4} - 625 = 0

What are the solutions to the equation roots x^3-3x^2+x-3 ?
The solutions to the equation roots x^3-3x^2+x-3 are x=3,x=i,x=-i
Find the zeros of roots x^3-3x^2+x-3
The zeros of roots x^3-3x^2+x-3 are x=3,x=i,x=-i