What are the solutions to the equation x^3-15x^2+79x-145=0 ?

The solutions to the equation x^3-15x^2+79x-145=0 are x=5,x=5+2i,x=5-2i

Find the zeros of x^3-15x^2+79x-145=0

The zeros of x^3-15x^2+79x-145=0 are x=5,x=5+2i,x=5-2i

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x^{3} - 15 x^{2} + 79 x - 145 = 0

x = 5, x = 5 + 2 i, x = 5 - 2 i

Solution steps

x^{3} - 15 x^{2} + 79 x - 145 = 0

Factor

x^{3} - 15 x^{2} + 79 x - 145 : (x - 5) (x^{2} - 10 x + 29)

(x - 5) (x^{2} - 10 x + 29) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x^{2} - 10 x + 29 = 0

Solve

x - 5 = 0 : x = 5

Solve

x^{2} - 10 x + 29 = 0 : x = 5 + 2 i, x = 5 - 2 i

The solutions are

x = 5, x = 5 + 2 i, x = 5 - 2 i

r^{3} - 7 r^{2} + 16 r - 12 = 0

x^{5} - 3 x^{4} - 15 x^{3} + 45 x^{2} - 16 x + 48 = 0

x^{4} - x^{2} = 3 x^{3} - 3 x

m^{4} - 2 m^{2} - 8 = 0

(x + 3)^{4} + 2 (x + 3)^{2} - 8 = 0

What are the solutions to the equation x^3-15x^2+79x-145=0 ?
The solutions to the equation x^3-15x^2+79x-145=0 are x=5,x=5+2i,x=5-2i
Find the zeros of x^3-15x^2+79x-145=0
The zeros of x^3-15x^2+79x-145=0 are x=5,x=5+2i,x=5-2i