What are the solutions to the equation factor x^3+3x^2-4x-12=0 ?

The solutions to the equation factor x^3+3x^2-4x-12=0 are x=-3,x=-2,x=2

Find the zeros of factor x^3+3x^2-4x-12=0

The zeros of factor x^3+3x^2-4x-12=0 are x=-3,x=-2,x=2

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factor

x^{3} + 3 x^{2} - 4 x - 12 = 0

x = - 3, x = - 2, x = 2

Solution steps

x^{3} + 3 x^{2} - 4 x - 12 = 0

Factor

x^{3} + 3 x^{2} - 4 x - 12 : (x + 3) (x + 2) (x - 2)

(x + 3) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - 3, x = - 2, x = 2

D, 2 b - hb = D^{3}

5 x^{4} - 9 x^{2} + 4

x^{3} - 5 x^{2} - 36 x = 0

x^{3} - 5 x^{2} + 6 x - 30 = 0

r^{3} - 3 r + 2 = 0

What are the solutions to the equation factor x^3+3x^2-4x-12=0 ?
The solutions to the equation factor x^3+3x^2-4x-12=0 are x=-3,x=-2,x=2
Find the zeros of factor x^3+3x^2-4x-12=0
The zeros of factor x^3+3x^2-4x-12=0 are x=-3,x=-2,x=2