What are the solutions to the equation x^3-3x^2+7x-5=0 ?

The solutions to the equation x^3-3x^2+7x-5=0 are x=1,x=1+2i,x=1-2i

Find the zeros of x^3-3x^2+7x-5=0

The zeros of x^3-3x^2+7x-5=0 are x=1,x=1+2i,x=1-2i

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x^{3} - 3 x^{2} + 7 x - 5 = 0

x = 1, x = 1 + 2 i, x = 1 - 2 i

Solution steps

x^{3} - 3 x^{2} + 7 x - 5 = 0

Factor

x^{3} - 3 x^{2} + 7 x - 5 : (x - 1) (x^{2} - 2 x + 5)

(x - 1) (x^{2} - 2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{2} - 2 x + 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{2} - 2 x + 5 = 0 : x = 1 + 2 i, x = 1 - 2 i

The solutions are

x = 1, x = 1 + 2 i, x = 1 - 2 i

x^{4} - 65 x^{2} + 64 = 0

x^{3} + 9 x^{2} + 24 x + 15 = 0

x^{4} - 8 x^{3} + 17 x^{2} + 2 x - 24 = 0

x^{3} + 19 x^{2} + 103 x - 135 = 0

2 x^{3} - 3 = 0

What are the solutions to the equation x^3-3x^2+7x-5=0 ?
The solutions to the equation x^3-3x^2+7x-5=0 are x=1,x=1+2i,x=1-2i
Find the zeros of x^3-3x^2+7x-5=0
The zeros of x^3-3x^2+7x-5=0 are x=1,x=1+2i,x=1-2i