What are the solutions to the equation roots x^3+125 ?

The solutions to the equation roots x^3+125 are x=-5,x= 5/2-(5sqrt(3))/2 i,x= 5/2+(5sqrt(3))/2 i

Find the zeros of roots x^3+125

The zeros of roots x^3+125 are x=-5,x= 5/2-(5sqrt(3))/2 i,x= 5/2+(5sqrt(3))/2 i

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roots

x^{3} + 125

x = - 5, x = \frac{5}{2} - \frac{5 3}{2} i, x = \frac{5}{2} + \frac{5 3}{2} i

Solution steps

x^{3} + 125

The roots are the intercepts with the x-axis

(y = 0)

x^{3} + 125 = 0

Move

125

to the right side

x^{3} = - 125

For

x^{3} = f (a)

the solutions are

Simplify

x = - 5, x = \frac{5}{2} - \frac{5 3}{2} i, x = \frac{5}{2} + \frac{5 3}{2} i

x^{3} = - 8 i

2 x^{3} - 10 x^{2} - 72 x = 0

x + (2 x^{2} - 3)^{3} = 0

- 4 x^{3} + 16 x = 0

x^{4} - 5 x^{2} - 36

What are the solutions to the equation roots x^3+125 ?
The solutions to the equation roots x^3+125 are x=-5,x= 5/2-(5sqrt(3))/2 i,x= 5/2+(5sqrt(3))/2 i
Find the zeros of roots x^3+125
The zeros of roots x^3+125 are x=-5,x= 5/2-(5sqrt(3))/2 i,x= 5/2+(5sqrt(3))/2 i