What are the solutions to the equation x^2+11x+24=0 ?

The solutions to the equation x^2+11x+24=0 are x=-3,x=-8

Find the zeros of x^2+11x+24=0

The zeros of x^2+11x+24=0 are x=-3,x=-8

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x^{2} + 11 x + 24 = 0

x = - 3, x = - 8

Solution steps

x^{2} + 11 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 24 = 5

x_{1, 2} = \frac{- 11 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 5}{2 \cdot 1}, x_{2} = \frac{- 11 - 5}{2 \cdot 1}

x = \frac{- 11 + 5}{2 \cdot 1} : - 3

x = \frac{- 11 - 5}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 3, x = - 8

\frac{- 48 c ^{2} d ^{4}}{- 8 c d}

\frac{2 x}{9} + \frac{1}{3} = \frac{4}{15}

56 \geq - 4 b

\frac{- 92 + 9 2 ^{2} - 4 ( 14 \cdot 14 )}{2 ( 14 )}

x^{4} - v^{4}

What are the solutions to the equation x^2+11x+24=0 ?
The solutions to the equation x^2+11x+24=0 are x=-3,x=-8
Find the zeros of x^2+11x+24=0
The zeros of x^2+11x+24=0 are x=-3,x=-8