What are the solutions to the equation m^3-m^2+2m-2=0 ?

The solutions to the equation m^3-m^2+2m-2=0 are m=1,m=sqrt(2)i,m=-sqrt(2)i

Find the zeros of m^3-m^2+2m-2=0

The zeros of m^3-m^2+2m-2=0 are m=1,m=sqrt(2)i,m=-sqrt(2)i

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m^{3} - m^{2} + 2 m - 2 = 0

m = 1, m = 2 i, m = - 2 i

Solution steps

m^{3} - m^{2} + 2 m - 2 = 0

Factor

m^{3} - m^{2} + 2 m - 2 : (m - 1) (m^{2} + 2)

(m - 1) (m^{2} + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m - 1 = 0 or m^{2} + 2 = 0

Solve

m - 1 = 0 : m = 1

Solve

m^{2} + 2 = 0 : m = 2 i, m = - 2 i

The solutions are

m = 1, m = 2 i, m = - 2 i

x^{3} - 2 x^{2} + x - 3 = 0

t^{3} = - 1

2 x^{3} - 2 = 0

4 x^{3} + 8 x^{2} - 9 x - 18 = 0

4 x^{3} - 12 x^{2} - 2 x + 6 = 0

What are the solutions to the equation m^3-m^2+2m-2=0 ?
The solutions to the equation m^3-m^2+2m-2=0 are m=1,m=sqrt(2)i,m=-sqrt(2)i
Find the zeros of m^3-m^2+2m-2=0
The zeros of m^3-m^2+2m-2=0 are m=1,m=sqrt(2)i,m=-sqrt(2)i