What are the solutions to the equation x^3+4x^2-3x-12=0 ?

The solutions to the equation x^3+4x^2-3x-12=0 are x=-4,x=-sqrt(3),x=sqrt(3)

Find the zeros of x^3+4x^2-3x-12=0

The zeros of x^3+4x^2-3x-12=0 are x=-4,x=-sqrt(3),x=sqrt(3)

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x^{3} + 4 x^{2} - 3 x - 12 = 0

x = - 4, x = - 3, x = 3

Decimal Notation

x = - 4, x = - 1.73205 \dots, x = 1.73205 \dots

Solution steps

x^{3} + 4 x^{2} - 3 x - 12 = 0

Factor

x^{3} + 4 x^{2} - 3 x - 12 : (x + 4) (x + 3) (x - 3)

(x + 4) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 4, x = - 3, x = 3

- 3 x^{4} + x^{3} - 187 x^{2} + 495 x + 414 = 0

x^{4} + 3 x^{3} - 6 x^{2} + 12 x - 40

125 x^{10} - 3 x^{7} = 0

x^{3} - 9 x^{2} + 28 x - 30 = 0

(- 2 x^{4} + 3 x^{2} + 8)^{2} = 0

What are the solutions to the equation x^3+4x^2-3x-12=0 ?
The solutions to the equation x^3+4x^2-3x-12=0 are x=-4,x=-sqrt(3),x=sqrt(3)
Find the zeros of x^3+4x^2-3x-12=0
The zeros of x^3+4x^2-3x-12=0 are x=-4,x=-sqrt(3),x=sqrt(3)