What are the solutions to the equation x^4-x-2=0 ?

The solutions to the equation x^4-x-2=0 are x=-1,x\approx 1.35320…

Find the zeros of x^4-x-2=0

The zeros of x^4-x-2=0 are x=-1,x\approx 1.35320…

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x^{4} - x - 2 = 0

x = - 1, x \approx 1.35320 \dots

Solution steps

x^{4} - x - 2 = 0

Factor

x^{4} - x - 2 : (x + 1) (x^{3} - x^{2} + x - 2)

(x + 1) (x^{3} - x^{2} + x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{3} - x^{2} + x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{3} - x^{2} + x - 2 = 0 : x \approx 1.35320 \dots

The solutions are

x = - 1, x \approx 1.35320 \dots

- \frac{3}{4} x^{5} = 96

x^{3} + x = 0

y, x^{3} - y^{3} = 0

- x^{3} + 5 x^{2} + x - 5 = 0

r^{3} - r^{2} - r + 1

What are the solutions to the equation x^4-x-2=0 ?
The solutions to the equation x^4-x-2=0 are x=-1,x\approx 1.35320…
Find the zeros of x^4-x-2=0
The zeros of x^4-x-2=0 are x=-1,x\approx 1.35320…