What are the solutions to the equation 4x^3-9x^2+4=0 ?

The solutions to the equation 4x^3-9x^2+4=0 are x=2,x=(1+sqrt(33))/8 ,x=(1-sqrt(33))/8

Find the zeros of 4x^3-9x^2+4=0

The zeros of 4x^3-9x^2+4=0 are x=2,x=(1+sqrt(33))/8 ,x=(1-sqrt(33))/8

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4 x^{3} - 9 x^{2} + 4 = 0

x = 2, x = \frac{1 + 33}{8}, x = \frac{1 - 33}{8}

Decimal Notation

x = 2, x = 0.84307 \dots, x = - 0.59307 \dots

Solution steps

4 x^{3} - 9 x^{2} + 4 = 0

Factor

4 x^{3} - 9 x^{2} + 4 : (x - 2) (4 x^{2} - x - 2)

(x - 2) (4 x^{2} - x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 4 x^{2} - x - 2 = 0

Solve

x - 2 = 0 : x = 2

Solve

4 x^{2} - x - 2 = 0 : x = \frac{1 + 33}{8}, x = \frac{1 - 33}{8}

The solutions are

x = 2, x = \frac{1 + 33}{8}, x = \frac{1 - 33}{8}

a^{6} = 30

- x^{3} + 2 x^{2} + 7 x + 4 = 0

3 x^{3} + 4 x^{2} - 9 x - 12 = 0

- 2 x^{3} - 2 x^{2} + 2 x + 8 = 0

x^{4} - 4 x^{3} - x^{2} + 16 x - 12 = 0

What are the solutions to the equation 4x^3-9x^2+4=0 ?
The solutions to the equation 4x^3-9x^2+4=0 are x=2,x=(1+sqrt(33))/8 ,x=(1-sqrt(33))/8
Find the zeros of 4x^3-9x^2+4=0
The zeros of 4x^3-9x^2+4=0 are x=2,x=(1+sqrt(33))/8 ,x=(1-sqrt(33))/8