What are the solutions to the equation roots x^3+x^2-9x-9 ?

The solutions to the equation roots x^3+x^2-9x-9 are x=-1,x=-3,x=3

Find the zeros of roots x^3+x^2-9x-9

The zeros of roots x^3+x^2-9x-9 are x=-1,x=-3,x=3

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roots

x^{3} + x^{2} - 9 x - 9

x = - 1, x = - 3, x = 3

Solution steps

x^{3} + x^{2} - 9 x - 9

The roots are the intercepts with the x-axis

(y = 0)

x^{3} + x^{2} - 9 x - 9 = 0

Factor

x^{3} + x^{2} - 9 x - 9 : (x + 1) (x + 3) (x - 3)

(x + 1) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 1, x = - 3, x = 3

x^{3} - 16 x^{2} + 75 x - 90 = 0

x, \frac{d ^{2} x}{d t ^{2}} = 2 x^{3}

x^{4} + 11 x^{2} = 0

x^{3} - x = 0

x^{3} - 2 x^{2} + 5 x - 3 = 0

What are the solutions to the equation roots x^3+x^2-9x-9 ?
The solutions to the equation roots x^3+x^2-9x-9 are x=-1,x=-3,x=3
Find the zeros of roots x^3+x^2-9x-9
The zeros of roots x^3+x^2-9x-9 are x=-1,x=-3,x=3